3^x=(3/2x)+6

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Solution for 3^x=(3/2x)+6 equation: 



3^x=(3/2x)+6

We move all terms to the left:

3^x-((3/2x)+6)=0



Domain of the equation: 2x)+6)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3^x-((+3/2x)+6)=0

We multiply all the terms by the denominator


3^x*2x)+6)-((+3=0

Wy multiply elements

6x^2+3=0

a = 6; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·6·3
Δ = -72
Delta is less than zero, so there is no solution for the equation

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